Answer
$x=200.8$
Work Step by Step
Recall the definition of a logarithm (pg. 451):
$\log_{b}{x}=y$ iff $b^y=x$
Applying this definition to our equation, we get:
$10^3=5x-4$
$10^3+4=5x$
$\frac{1}{5}(10^3+4)=x$
$x=\frac{1004}{5}=200.8$
We confirm that the answer works:
$\log_{10} (5\cdot200.8-4)=3$
$\log_{10} (1004-4)=3$
$\log_{10} (1000)=3$
$3=3$