Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-5 Exponential and Logarithmic Equations - Practice and Problem-Solving Exercises - Page 475: 64

Answer

$x\approx 2.9315$

Work Step by Step

We are asked to solve: $8^x=444$ Recall the definition of a logarithm (pg. 451): $\log_{b}{x}=y$ iff $b^y=x$ Applying this definition to our equation, we get: $\log_{8}{444}=x$ Next, recall the change of base formula (pg. 464): $\log_{b}{m}=\frac{\log_{c}{m}}{\log_{c}{b}}$ Applying this property, we get: $\frac{\log_{10}{444}}{\log_{10}{8}}=x$ $x\approx 2.9315$ We confirm that the answer works: $8^{2.9315}=444$ $444=444$
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