Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 424: 43

Answer

$x^3y^6$

Work Step by Step

Recall: (1) $a^{\frac{m}{n}}=\sqrt[n]{a^m}$ (2) $\left(a^m\right)^n=a^{mn}$ (3) $\left(\dfrac{a}{b}\right)^m=\dfrac{a^m}{b^m}$ (4) $a^{-m} = \dfrac{1}{a^m}$ Use rule (3) above to obtain: \begin{align*} &=\dfrac{\left(x^{\frac{1}{3}}\right)^9}{\left(y^{-\frac{2}{3}}\right)^9} \end{align*} Use rule (2) above to obtain: \begin{align*} \dfrac{\left(x^{\frac{1}{3}}\right)^9}{\left(y^{-\frac{2}{3}}\right)^9}&=\dfrac{x^{\frac{1}{3}(9)}}{y^{-\frac{2}{3}(9)}}\\\\ &=\dfrac{x^3}{y^{-6}} \end{align*} Use rule (4) above to obtain: \begin{align*} &=\dfrac{x^3}{\frac{1}{y^6}}\\\\ &=x^3 \cdot \dfrac{y^6}{1}\\\\ &=x^3y^6 \end{align*}
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