Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 424: 26

Answer

$22\sqrt3$

Work Step by Step

Factor each radicand (expression inside the radical sign) so that one of the factors is a perfect square to obtain: \begin{align*} &=10\sqrt{9(3)}-4\sqrt{4(3)}\\ &=10\sqrt{3^2(3)}-4\sqrt{2^2(3)} \end{align*} Simplify each radical to obtain: \begin{align*} &=10(3)\sqrt{3}-4(2)\sqrt{3}\\ &=30\sqrt3 - 8\sqrt3 \end{align*} Combine like terms: \begin{align*} &=(30-8)(\sqrt3)\\ &=22\sqrt3 \end{align*}
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