Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 424: 32

$\dfrac{2\sqrt5+5}{5}$

Rationalize the denominator by multiplying $\sqrt5$ to both the numerator and denominator to obtain: \begin{align*} &=\dfrac{2+\sqrt5}{\sqrt5} \cdot \dfrac{\sqrt5}{\sqrt5}\\\\ &=\dfrac{(2+\sqrt5)(\sqrt5)}{\sqrt{25}}\\\\ &=\dfrac{2(\sqrt5)+\sqrt5(\sqrt5)}{5}\\\\ &=\dfrac{2\sqrt5+\sqrt{25}}{5}\\\\ &=\dfrac{2\sqrt5+5}{5} \end{align*}