Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 424: 30

Answer

$-6$

Work Step by Step

Recall: $(a-b)(a+b) = a^2-b^2$ Use the rule above with $a=\sqrt5$ and $b=\sqrt{11}$ to obtain: \begin{align*} &=(\sqrt5)^2-(\sqrt{11})^2\\ &=5-11\\ &=-6 \end{align*}
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