Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 424: 29

Answer

$14+7\sqrt2$

Work Step by Step

Recall: $(a+b)(c+d) = a(c+d) + b(c+d)$ Use the rule above to obtain: \begin{align*} &=3(4+\sqrt2) +\sqrt2(4+\sqrt2)\\ &=3(4)+3(\sqrt2)+\sqrt2(4)+\sqrt2(\sqrt2)\\ &=12+3\sqrt2+4\sqrt2+\sqrt4\\ &=12+3\sqrt2+4\sqrt2+2\\ &=14+3\sqrt2+4\sqrt2 \end{align*} Combine like terms to obtain: \begin{align*} &=14+(3+4)(\sqrt2)\\ &=14+7\sqrt2 \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.