Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 424: 27

Answer

$26\sqrt{5x}$

Work Step by Step

Factor each radicand (expression inside the radical sign) so that one of the factors is a perfect square to obtain: \begin{align*} &=3\sqrt{4(5x)}+8\sqrt{9(5x)}-4\sqrt{5x}\\ &=3\sqrt{2^2(5x)}+8\sqrt{3^2(5x)}-4\sqrt{5x}\\ \end{align*} Simplify each radical to obtain: \begin{align*} &=3(2)\sqrt{5x}+8(3)\sqrt{5x}-4\sqrt{5x}\\ &=6\sqrt{5x}+24\sqrt{5x}-4\sqrt{5x}\\ \end{align*} Combine like terms: \begin{align*} &=(6+24-4)(\sqrt{5x})\\ &=26\sqrt{5x} \end{align*}
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