Answer
$\dfrac{1}{x}$
Work Step by Step
Recall:
(1) $a^{\frac{m}{n}}=\sqrt[n]{a^m}$
(2) $\left(a^m\right)^n=a^{mn}$
(3) $\dfrac{a^m}{a^n}=a^{m-n}$
(4) $a^{-m} = \dfrac{1}{a^m}$
Use rule (3) above to obtain:
\begin{align*}
&=\left(x^{4-(-1)}\right)^{-\frac{1}{5}}\\
&=\left(x^{4+1}\right)^{-\frac{1}{5}}\\
&=\left(x^5\right)^{-\frac{1}{5}}
\end{align*}
Use rule (2) above to obtain:
\begin{align*}
\left(x^5\right)^{-\frac{1}{5}}&=x^{5\left(-\frac{1}{5}\right)}\\
&=x^{-1}
\end{align*}
Use rule (4) above to obtain:
\begin{align*}
&=\dfrac{1}{x^1}\\\\
&=\dfrac{1}{x}
\end{align*}
