Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 424: 28

Answer

$x\sqrt[3]{2}$

Work Step by Step

Factor each radicand (expression inside the radical sign) so that one of the factors is a perfect square to obtain: \begin{align*} &=\sqrt[3]{27x^3(2)}-\sqrt[3]{8x^3(2)}\\ &=\sqrt[3]{(3x)^3(2)}-\sqrt[3]{(2x)^3(2)}\\ \end{align*} Simplify each radical to obtain: \begin{align*} &=3x\sqrt[3]{2}-2x\sqrt[3]{2}\\ \end{align*} Combine like terms: \begin{align*} &=(3x-2x)(\sqrt[3]{2})\\ &=x\sqrt[3]{2} \end{align*}
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