## Algebra 2 Common Core

Given: $3x + 2y = 10$ $6x + 4y = 15$ Multiply the first equation, $3x + 2y = 10$, by $2$. $6x + 4y = 20$ Subtract the first equation, $6x + 4y = 20$, from the second equation, $6x + 4y = 15$. $6x + 4x - (6x + 4x) = 15 - (20) \\6x+4x-(6x+4x)=-5$ Subtract each term of the binomial: $6x - 6x + 4x - 4x = -5$ Combine like terms: $0 = -5$ This is a contradiction, as obviously $0 \ne -5$. Thus, there are no solutions.