Chapter 3 - Linear Systems - 3-2 Solving Systems Algebraically - Practice and Problem-Solving Exercises - Page 146: 22

$x = 7$, $y=5$

Given: $x + y = 12$ $x - y = 2$ Add the equations together by adding the corresponding parts: $x + y + (x - y) = 12 + (2) \\2x=14$ Divide both sides by 2: $x = 7$ Substitute $7$ into $x$ of the first equation: $(7) + y = 12$ Subtract 7 to both sides: $y = 5$ Thus, $x = 7$, $y=5$