Answer
No solutions.
Work Step by Step
Given:
$6x - 2y = 11$
$-9x + 3y = 16$
Multiply both sides of the first equation, $6x - 2y = 11$, by $3$:
$18x - 6y = 33$
Multiply both sides of the second equation, $-9x + 3y = 16$, by $2$:
$-18x + 6y = 32$
Add the first equation, $18x - 6y = 33$, to the second equation, $-18x + 6y = 32$:
$-18x + 6y + (18x - 6x) = 32 + (33)$
$-18x + 6y + (18x - 6x) = 65$
Add each term of the binomial:
$-18x + 18x + 6y + (- 6y) = 65$
$-18x + 18x + 6y - 6y = 65$
Combine like terms:
$0 = 65$
This is a contradiction, as obviously, $0 \ne 65$.
Thus, there are no solutions.
