## Algebra 2 Common Core

Given: $6x - 2y = 11$ $-9x + 3y = 16$ Multiply both sides of the first equation, $6x - 2y = 11$, by $3$: $18x - 6y = 33$ Multiply both sides of the second equation, $-9x + 3y = 16$, by $2$: $-18x + 6y = 32$ Add the first equation, $18x - 6y = 33$, to the second equation, $-18x + 6y = 32$: $-18x + 6y + (18x - 6x) = 32 + (33)$ $-18x + 6y + (18x - 6x) = 65$ Add each term of the binomial: $-18x + 18x + 6y + (- 6y) = 65$ $-18x + 18x + 6y - 6y = 65$ Combine like terms: $0 = 65$ This is a contradiction, as obviously, $0 \ne 65$. Thus, there are no solutions.