Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-2 Solving Systems Algebraically - Practice and Problem-Solving Exercises: 25

Answer

$x = 2$, $y = -2$, or $(2,-2)$

Work Step by Step

Given: $4x + 2y = 4$ $6x + 2y = 8$ Subtract the first equation, $4x + 2y = 4$, from the second, $6x + 2y = 8$: $6x + 2y - (4x + 2y) = 8 - (4) \\6x +2y-4x-2y=4 \\(6x - 4x) + (2y - 2y) = 4 \\2x=4$ Divide both sides by $2$: $x = 2$ Substitute $x = 2$ back into first equation: $4x + 2y = 4 4(2) + 2y = 4 \\8+2y=4 \\2y=4-8 \\2y=-4$ Divide both sides by $2$: $y = -2$ Thus, $x = 2$, $y = -2$
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