## Algebra 2 Common Core

Published by Prentice Hall

# Chapter 3 - Linear Systems - 3-2 Solving Systems Algebraically - Practice and Problem-Solving Exercises: 34

No solutions.

#### Work Step by Step

Given: $2x - 3y = 6$ $6x - 9y = 9$ Multiply the first equation by $3$: $6x - 9y = 18$ Subtract the second equation from the first: $6x - 9y - (6x - 9y) = 18 - (9)$ Expand: $6x - 6x - 9x + 9x = 18 - 9$ Simplify: $0 = 9$ This is a contradiction, as obviously $0 \ne 9$, and thus, there are no solutions.

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