Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-2 Solving Systems Algebraically - Practice and Problem-Solving Exercises - Page 146: 14


y=-1; x=10

Work Step by Step

We are given two equations, x+3y =7 and 2x-4y=24, both of which have two variables in them. In order to solve this system of linear equations, we must put one expression in terms of one variable. Using the expression x+3y =7, we subtract 3y to obtain x=7-3y. We plug x=7-3y into 2x-4y=24 to obtain that 2(7-3y)-4y = 24. We solve to find that y=-1. We now substitute y=-1 into x=7-3y to obtain that x equals 10.
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