Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises: 38

Answer

2x(2x+3)(x+4)

Work Step by Step

Given the polynomial $4x^{3}$ + $22x^{2}$ + 24x We see that the three terms have a common factor of 2x so we factor out a 2x. 2x($2x^{2}$ + 11x + 12) *** We break of the middle term into two factors that add to give +11 and multiply to give +24. The two numbers are +8 and +3. 2x($2x^{2}$ + 3x + 8x + 12) We take the GCD of the first two and the GCD of the last two terms. 2x(x(2x+3)+4(2x+3)) We take (2x+3) and factor it out which gives us. 2(2x+3)(x+4)
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