## Algebra 1

a) $(4x-1)(5x^{2}+11)$ b) $(4x-1)(5x^{2}+11)$
a) $20x^{3} - 5x^{2} + 44x - 11$ Group the first two terms and last two terms together $(20x^{3} - 5x^{2}) + (44x - 11)$ Factor out the GCF from the first two terms and last two terms $5x^{2}( 4x-1) +11( 4x-1)$ Take out (4x-1) common factor and that gives us $(4x-1)(5x^{2}+11)$ b) By adding the second set of polynomials we see that we end up with the same polynomial $20x^{3} - 5x^{2} + 44x - 11$ Group the first two terms and last two terms together $(20x^{3} - 5x^{2}) + (44x - 11)$ Factor out the GCF from the first two terms and last two terms $5x^{2}( 4x-1) +11( 4x-1)$ Take out (4x-1) common factor and that gives us $(4x-1)(5x^{2}+11)$