Answer
$9t(t-8)(t-2)$
Work Step by Step
Given:
$9t(t^{2}-10t+16)$
Now, $1\times16=$$-2\times-8$
Therefore, break the term $-10t$ as $(-2t-8t)$
This becomes:
$=9t(t^{2}-2t-8t+16)$
$=9t(t(t-2)-8(t-2))$
$=9t((t-8)(t-2))$
$=9t(t-8)(t-2)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 31
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