Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises: 24

Answer

$(5g)(g^{2}+4)(g-1)$

Work Step by Step

After grouping : $=(5g^{4}-5g^{3})+(20g^{2}-20g)$ $=5g^{3}(g-1)+20g(g-1)$ $=(5g^{3}+20g)(g-1)$ $=(5g)(g^{2}+4)(g-1)$
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