Answer
$(5g)(g^{2}+4)(g-1)$
Work Step by Step
After grouping :
$=(5g^{4}-5g^{3})+(20g^{2}-20g)$
$=5g^{3}(g-1)+20g(g-1)$
$=(5g^{3}+20g)(g-1)$
$=(5g)(g^{2}+4)(g-1)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 24
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