## Algebra 1

$(5g)(g^{2}+4)(g-1)$
After grouping : $=(5g^{4}-5g^{3})+(20g^{2}-20g)$ $=5g^{3}(g-1)+20g(g-1)$ $=(5g^{3}+20g)(g-1)$ $=(5g)(g^{2}+4)(g-1)$