Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 26

$6(3v^{2}+4)(2v-7)$

$36v^{3}=2.2.3.3.v.v.v$ and $126v^{2}=$$2.3.3.7.v.v$ Hence, $GCF=$$2.3.3.v.v=18v^{2}$ $48v=2.2.2.2.3.v$ and $168=2.2.2.3.7$ Hence, $GCF=$$2.2.2.3=24$ After grouping: $=(36v^{3}-126v^{2})+(48v-168)$ $=18v^{2}(2v-7)+24(2v-7)$ $=(18v^{2}+24)(2v-7)$ $=6(3v^{2}+4)(2v-7)$