Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 30



Work Step by Step

Given expression: $2x(3x^{2}+19x-14)$ Now, $-14\times3=$$-2\times21$ Therefore, write $19x$ as $(-2x+21x)$ This becomes : $=2x(3x^{2}-2x+21x-14)$ $=2x(x(3x-2)+7(3x-2))$ $=2x((x+7)(3x-2))$ $=2x(x+7)(3x-2)$
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