Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 32



Work Step by Step

Given : $6y(10y^{3}-50y^{2}-7y+35)$ This becomes : $=6y(10y^{2}(y-5)-7(y-5))$ $=6y((10y^{2}-7)(y-5))$ $=6y(10y^{2}-7)(y-5)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.