Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises: 32

Answer

$6y(10y^{2}-7)(y-5)$

Work Step by Step

Given : $6y(10y^{3}-50y^{2}-7y+35)$ This becomes : $=6y(10y^{2}(y-5)-7(y-5))$ $=6y((10y^{2}-7)(y-5))$ $=6y(10y^{2}-7)(y-5)$
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