## Algebra 1

$4c(c+5)(c+8)$
Given expression : $4c(c^{2}+13c+40)$ Now $1.40 = 8.5$ Therefore, break the $13c$ term as $(8c+5c)$ This becomes: $=4c(c^{2}+5c+8c+40)$ $=4c(c(c+5)+8(c+5))$ $=4c((c+8)(c+5))$ $=4c(c+5)(c+8)$