Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 29



Work Step by Step

Given expression : $4c(c^{2}+13c+40)$ Now $1.40 = 8.5$ Therefore, break the $13c$ term as $(8c+5c)$ This becomes: $=4c(c^{2}+5c+8c+40)$ $=4c(c(c+5)+8(c+5))$ $=4c((c+8)(c+5))$ $=4c(c+5)(c+8)$
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