## Algebra 1

Given the polynomial $(5r)^{2}$ + 30r + $(3)^{2}$ We see that the polynomial has the first and last term squared and the middle term is +2 times the first and last term. Thus it follows the rule of $a^{2}$ + 2ab + $b^{2}$ = $(a+b)^{2}$ In this polynomial a= 5r and b=3 $(5r)^{2}$ + 2(5r)(3) + $(3)^{2}$ = $(5r+3)^{2}$ The formula for area of a square is $Length^{2}$ so to get the length of one side we square root the answer. $\sqrt (5r+3)^{2}$ = (5r+3)