Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 514: 19



Work Step by Step

Given the polynomial $(5z)^{2}$ + 40z + $(4)^{2}$ We see that the polynomial has the first and last term squared and the middle term is +2 times the first and last term. Thus it follows the rule of $a^{2}$+2ab+$b^{2}$=$(a+b)^{2}$ In this polynomial a= 5z and b=4 $(5z)^{2}$ + 2(5z)(4) + $(4)^{2}$ = $(5z+4)^{2}$
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