## Algebra 1

Given the polynomial $d^{2}$ - 20d + 100 *** We break of the middle term into two factors that add to give -20 and multiply to give +100. The two numbers are -10 and -10. $d^{2}$ - 10d - 10d + 100 We take the GCD of the first two and the GCD of the last two terms. d(d-10) -10(d-10) We take (d-10) and factor it out which gives us. (d-10)(d-10)