Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 514: 17



Work Step by Step

Given the polynomial $(3n)^{2}$ - 42n + $(7)^{2}$ We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$-2ab+$b^{2}$=$(a-b)^{2}$ In this polynomial a= 3n and b=7 $(3n)^{2}$ - 2(3n)(7) + $(7)^{2}$ = $(3n-7)^{2}$
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