Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 514: 18



Work Step by Step

Given the polynomial $(6s)^{2}$ - 60s + $(5)^{2}$ We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$-2ab+$b^{2}$=$(a-b)^{2}$ In this polynomial a= 6s and b=5 $(6s)^{2}$ - 2(6s)(5) + $(5)^{2}$ = $(6s-5)^{2}$
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