Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises - Page 514: 10

(v-5)(v-5)

Given the polynomial $v^{2}$ - 10v + 25 *** We break of the middle term into two factors that add to give -10 and multiply to give +25. The two numbers are -5 and -5. $v^{2}$ - 5v - 5v + 25 We take the GCD of the first two and the GCD of the last two terms. v(v-5) -5(v-5) We take (v-5) and factor it out which gives us. (v-5)(v-5)