#### Answer

$(8x+7)^{2}$

#### Work Step by Step

Given the polynomial
$(8x)^{2}$ + 112x + $(7)^{2}$
We see that the polynomial has the first and last term squared and the middle term is +2 times the first and last term. Thus it follows the rule of
$a^{2}$+2ab+$b^{2}$=$(a+b)^{2}$
In this polynomial a= 8x and b=7
$(8x)^{2}$ + 2(8x)(7) + $(7)^{2}$ = $(8x+7)^{2}$