Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-7 Factoring Special Cases - Practice and Problem-Solving Exercises: 21

Answer

The length of one side of the square is (10r-11)

Work Step by Step

Given the polynomial $(10r)^{2}$ - 220r + $(11)^{2}$ We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ In this polynomial a= 10r and b=11 $(10r)^{2}$ - 2(10r)(11) + $(11)^{2}$ = $(10r-11)^{2}$ Since the area of a square is $Length^{2}$. The length of one side is the square root of the answer. $\sqrt (10r-11)^{2}$ = $(10r-11)^{2}$
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