## Algebra 1

Given the polynomial $(10r)^{2}$ - 220r + $(11)^{2}$ We see that the polynomial has the first and last term squared and the middle term is -2 times the first and last term. Thus it follows the rule of $a^{2}$ - 2ab + $b^{2}$ = $(a-b)^{2}$ In this polynomial a= 10r and b=11 $(10r)^{2}$ - 2(10r)(11) + $(11)^{2}$ = $(10r-11)^{2}$ Since the area of a square is $Length^{2}$. The length of one side is the square root of the answer. $\sqrt (10r-11)^{2}$ = $(10r-11)^{2}$