## Algebra 1

Undefined or no solution when $a=3$ and one solution for all real number excluding $a=3$.
Given: $\frac{x}{3-a}=\frac{x}{3-a}$ The given equation becomes true when $x=3$ but when we put $a=3$, so $\frac{3}{3-3}=\frac{3}{3-3} \implies \frac{3}{0}=\frac{3}{0}$; undefined solution. Hence, we get undefined or no solution when $a=3$ and one solution for all real number excluding $a=3$.