Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Chapter Test - Page 707: 17



Work Step by Step

As we are given that $\frac{9}{n}-\frac{8}{n+1}$ LCD $= n(n+1)$ $=\dfrac{9(n+1)}{n(n+1)}-\dfrac{8n}{n(n+1)}$ After simplifications, we get $=\dfrac{9(n+1)-8n}{n(n+1)}$ $=\dfrac{n+9}{n(n+1)}$
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