#### Answer

$\dfrac{n+9}{n(n+1)}$

#### Work Step by Step

As we are given that $\frac{9}{n}-\frac{8}{n+1}$
LCD $= n(n+1)$
$=\dfrac{9(n+1)}{n(n+1)}-\dfrac{8n}{n(n+1)}$
After simplifications, we get
$=\dfrac{9(n+1)-8n}{n(n+1)}$
$=\dfrac{n+9}{n(n+1)}$

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Published by
Prentice Hall

ISBN 10:
0133500403

ISBN 13:
978-0-13350-040-0

$\dfrac{n+9}{n(n+1)}$

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