## Algebra 1

Undefined solution for $m=3$
Given: $\dfrac{m}{m-3}+\dfrac{1}{4}=\dfrac{m}{m-3}$ When he puts $m=3$, the equation does not satisfied which makes the denominator equals to $0$. That is, $\dfrac{m}{m-3}+\dfrac{1}{4}=\dfrac{m}{m-3}$ $\dfrac{3}{3-3}+\dfrac{1}{4}=\dfrac{3}{3-3}$ $\dfrac{3}{0}+\dfrac{1}{4}=\dfrac{3}{0}$ This represents an undefined solution for $m=3$