## Algebra 1

$v=-2,-6$
As we are given that $\frac{v}{3}+\frac{v}{v+5}=-\frac{4}{v+5}$ LCD $= 3(v+5)$ $\frac{v}{3}+\frac{v}{v+5}=-\frac{4}{v+5}\times (3)(v+5)$ $v^2+8v+12=0$ After factorization, we have $(v+6) (v+2)=0$ After simplifications, we get the solutions: $v=-2,-6$