## Algebra 1

$\dfrac{7b^2+6b-4}{3b(b+2)}$
As we are given that $\frac{4b-2}{3b}+\frac{b}{b+2}$ LCD $= 3b(b+2)$ $=\dfrac{4b-2(b+2)}{3b(b+2)}+\dfrac{(3b)b}{3b(b+2)}$ After simplifications, we get $=\dfrac{(4b-2)(b+2)+b(3b)}{3b(b+2)}$ $=\dfrac{4b^2+8b-2b-4+3b^2}{3b(b+2)}$ $=\dfrac{7b^2+6b-4}{3b(b+2)}$