Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Chapter Test - Page 707: 8


$\frac{6p-30}{3p-15}=2; p \ne 5$

Work Step by Step

Given: $\frac{6p-30}{3p-15}$ Consider denominator $(3p-15)=0$ to check the exclude value which makes the denominator $0$. $3p=15$ $p=\frac{15}{3}$ Thus, $p=5$ $\frac{6p-30}{3p-15} = \frac{6(p-5)}{3(p-5)}$ Hence, $\frac{6p-30}{3p-15}=2; p \ne 5$
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