## Algebra 1

$\dfrac{(x+2)}{4}$
As we are given that $\dfrac{3}{(x-2)} \times \dfrac {x^2-4}{12}$ As we know $a^2-b^2=(a-b)(a+b)$ Thus, $\dfrac{3}{(x-2)} \times \dfrac {x^2-4}{12}=\dfrac{3(x-2)(x+2)}{12(x-2)}$ $=\dfrac{(x+2)}{4}$