Answer
$\dfrac{1}{6x^2}$
Work Step by Step
As we are given that $\dfrac{5x}{(x^2+2x)} \div \dfrac {30x^2}{x+2}$
Write: $(x^2+2x)=x(x+2)$
Thus, $\dfrac{5x}{(x^2+2x)} \div \dfrac {30x^2}{x+2}=\dfrac{5x(x+2)}{x(x+2) \times 30x^2}$
$=\dfrac{1}{6x^2}$
