## Algebra 1: Common Core (15th Edition)

$\sqrt 2/t^{2}$
We can simplify the expression as follows = $(2\sqrt 24)/(\sqrt 48t^{4})$ = $(\sqrt 2\sqrt 2\sqrt 24)/(\sqrt 24\sqrt 2\sqrt t^{4})$ = $\sqrt 2/\sqrt t^{4}$ (Cancelling $\sqrt 24\sqrt 2$ in the numerator and the denominator) = $\sqrt 2/t^{2}$