Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 623: 30

Answer

= $ -180s\sqrt 5s$

Work Step by Step

Simplifying $ -6\sqrt 15s^3 \times 2 \sqrt 75$ ($-6\times2) (\sqrt 15s^3 \times \sqrt 75)$ = $ -12\sqrt 1125s^3$ Finding the perfect square factor of $1125s^3$ $1125s^3 = 5\times 225 \times s^3$ = $ 5 \times 15^2 \times s^2 \times s$ = $5s (15s)^2$ Continue Simplifying: $ -12\sqrt 1125s^3 = -12(\sqrt 5s \times \sqrt (15s)^2)$ = $-12( \sqrt 5s \times 15s)$ = $ -180s\sqrt 5s$
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