## Algebra 1: Common Core (15th Edition)

Answer is $7\sqrt 3/4$
We can simplify as follows: = $7\sqrt( 6 / 32)$ = $7\sqrt 6 / \sqrt 16*\sqrt 2$ = $7\sqrt 3*\sqrt 2 / \sqrt 16*\sqrt 2$ (since $\sqrt 2 \div \sqrt 2=1$ and $\sqrt 16=4)$ = $7\sqrt 3 / 4$.