Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 623: 37

Answer

Answer is $7\sqrt 3/4$

Work Step by Step

We can simplify as follows: = $7\sqrt( 6 / 32)$ = $7\sqrt 6 / \sqrt 16*\sqrt 2$ = $7\sqrt 3*\sqrt 2 / \sqrt 16*\sqrt 2$ (since $\sqrt 2 \div \sqrt 2=1$ and $\sqrt 16=4)$ = $7\sqrt 3 / 4$.
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