## Algebra 1: Common Core (15th Edition)

$77a/2$
We can simplify the expression as follows: = $11\sqrt (49a^{5}/4a^{3})$ = $11(\sqrt 49\sqrt a^{5}/\sqrt 4\sqrt a^{3})$ (Using the Multiplication Theorem $\sqrt x *\sqrt y = \sqrt xy$) = $11(7a^{2}\sqrt a/2a\sqrt a)$ = $11(7a/2)$ (Dividing by $a\sqrt a$) = $77a/2$.