Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 623: 41

Answer

$77a/2$

Work Step by Step

We can simplify the expression as follows: = $ 11\sqrt (49a^{5}/4a^{3})$ = $ 11(\sqrt 49\sqrt a^{5}/\sqrt 4\sqrt a^{3})$ (Using the Multiplication Theorem $\sqrt x *\sqrt y = \sqrt xy$) = $ 11(7a^{2}\sqrt a/2a\sqrt a)$ = $ 11(7a/2)$ (Dividing by $a\sqrt a$) = $ 77a/2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.