Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 623: 39

Answer

$\sqrt (3x)/8$

Work Step by Step

We can simplify the expression as follows: = $\sqrt (3x^{3} / 64x^{2})$ = $\sqrt 3\sqrt x^{2}\sqrt x / \sqrt 64\sqrt x^{2}$ $ \sqrt xy =\sqrt x * \sqrt y$) = $x\sqrt 3\sqrt x / 8x$ = $\sqrt (3x) / 8$. (Using the multiplication theorem, $\sqrt x * \sqrt y= \sqrt xy$)
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