## Algebra 1: Common Core (15th Edition)

$24c^{7}$
$-1/3 \times -6 \times \sqrt {18c^{5} \times 8 c^{9}} =2 \sqrt {144 c^{14}}$ We now separate the number and the variable into two separate square roots: $2 \sqrt {144} \times \sqrt {c^{14}} =2\sqrt {144} \times c^{7}$ We see if any of the factors of a radical are perfect squares (meaning that their square root will be an integer) to see if the radical is in its most simplified form. Because 144 is a perfect square, we know that we can simplify: $2 \sqrt {144} \times c^{7}= 24c^{7}$