Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 623: 12

Answer

$8 \sqrt {2}$

Work Step by Step

In order to see if a radical is in simplified form, see if any of its factors are perfect squares (meaning that their square root will be an integer). We see that 128 has factors of 64 and 2. 64 is a perfect square, so we know that we can simplify: $\sqrt {128} = \sqrt {64} \times \sqrt {2} = 8 \sqrt {2}$
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