Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises: 16

Answer

$ 8s \sqrt {3}$

Work Step by Step

We first separate the number and the variable into two separate square roots: $ \sqrt {192} \times \sqrt {s^{2}} = \sqrt {192} \times s$ In order to see if a radical is in simplified form, see if any of its factors are perfect squares (meaning that their square root will be an integer). We see that $\sqrt 192$ has factors of 64 and 3. 64 is a perfect square, so we know that we can simplify: $s\sqrt {192} = s \times \sqrt {64} \times \sqrt {3} = 8s \sqrt {3}$
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