Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 48

Answer

$y=1\pm2\sqrt{6}$

Work Step by Step

Getting the square root of both sides, the solution/s of the given equation, $ (y-1)^2=24 ,$ is/are \begin{array}{l}\require{cancel} y-1=\pm\sqrt{24} \\\\ y-1=\pm\sqrt{4\cdot6} \\\\ y-1=\pm\sqrt{(2)^2\cdot6} \\\\ y-1=\pm2\sqrt{6} \\\\ y=1\pm2\sqrt{6} .\end{array}
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