Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Cumulative Review - Page 534: 38c

Answer

$\sqrt[3] {xy^{2}}$

Work Step by Step

$\sqrt[6] {x^{2}y^{4}}=(x^{2}y^{4})^{\frac{1}{6}}=(x^{2})^{\frac{1}{6}}(y^{4})^{\frac{1}{6}}=(x)^{\frac{1}{3}}(y^{2})^{\frac{1}{3}}=\sqrt[3] {xy^{2}}$
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